SQLite

Consider the following test case:

CREATE TABLE t1 (c0);
CREATE INDEX i0 ON t1((LIKELIHOOD(c0, 100) IN ())); -- unexpected: no error
ALTER TABLE t1 RENAME COLUMN c0 TO c1; -- error occurs only here: second argument to likelihood() must be a constant between 0.0 and 1.0

I would expect that the index cannot be created, since an illegal argument is passed to LIKELIHOOD. However, this is not the case and only when an ALTER TABLE is executed does the illegal parameter result in an error.

Note that this problem also applies to SELECT queries:

SELECT * FROM t1 WHERE LIKELIHOOD(c0, 100) IN (); -- unexpected: also no error
SELECT * FROM t1 WHERE LIKELIHOOD(c0, 100) IS 1 -- expected: second argument to likelihood() must be a constant between 0.0 and 1.0

Fixed by [71643deb].

I found another, similar bug that was not addressed by the fix:

CREATE TABLE t0(c0);
CREATE INDEX i0 ON t0(((LIKELIHOOD(1, 2)) AND ((1 IN ())))); -- unexpected: no error
ALTER TABLE t0 RENAME TO t1; -- -- error occurs only here: second argument to likelihood() must be a constant between 0.0 and 1.0