SQLite Forum

DELETE FROM database WHERE rowid

DELETE FROM database WHERE rowid

(1) By gastonv on 2020-08-19 18:30:27 [link]

In adressen.py
I have:

import sqlite3

def wisadres(id):

    # Connect to database and create cursor
    conn = sqlite3.connect('adressen.db')
    c = conn.cursor()
    c.execute("DELETE FROM adressen WHERE rowid = (?)", id)
    # commit our command
    # close connection

Then, in order to run it, in adressenapp.py
I have:

import adressen


When I run this, row id 6 is deleted successfully.

>>> %Run adressenapp.py

Now I like to delete e.g. row 69 with:

import adressen


Now, with this command, I become an error message:

>>> %Run adressenapp.py
Traceback (most recent call last):
  File "/home/gastonv/Programmeren/Sqlite/adressenapp.py", line 19, in <module>
  File "/home/gastonv/Programmeren/Sqlite/adressen.py", line 100, in wisadres
    c.execute("DELETE FROM adressen WHERE rowid = (?)", id)
sqlite3.ProgrammingError: Incorrect number of bindings supplied. The current statement uses 1, and there are 2 supplied.

Please, what can be the reason why it doesn't works?
Many thanks in advance for each answer.
Kind regards,
Gaston Verhulst.

(2) By David Raymond (dvdraymond) on 2020-08-19 19:05:04 in reply to 1 [link]

The parameters argument in [Cursor.execute](https://docs.python.org/3.8/library/sqlite3.html#sqlite3.Cursor.execute) is a sequence of all the parameters that will be bound. It worked in the first example because a string is a sequence of single characters, and you gave it a single character string for a query with a single parameter.

In the second example you're giving it a query with 1 parameter, but a string which is a sequence of 2 characters. So you've got 2 things to bind, but only one place for them.

Correct use would be to have the single parameter you want to bind be in a 1 element list or tuple

`c.execute("DELETE FROM adressen WHERE rowid = ?;", (id,))`


`c.execute("DELETE FROM adressen WHERE rowid = ?;", [id])`

(And also, id should be converted to an integer since it's a rowid, but it works ok here)

(3) By gastonv on 2020-08-19 19:44:52 in reply to 2

Hello dear David Raymond,
I have to thank you very much for the quick reply.

In the mean time, I have done a test with your first suggestion with
 rowid = ?;", (id,)
and the result was a success.

Kind regards and many thanks for the fine communication.
Gaston Verhulst.